Unit 11: Review Exercises
Review Exercise 11 Solutions
Comprehensive solved review problems combining multiple choice questions, triangle construction, and advanced locus shading problems.
Question 1
Standard MCQ Answers
| Q# | MCQ Statement | Answer Key |
|---|---|---|
| i | Sum of measures of any two sides of a triangle is ___ the measure of third side. | greater than (b) |
| ii | An equilateral triangle ___ | can be isosceles (a) |
| iii | If sum of measures of two angles is less than 90°, then the triangle is ___ | obtuse angled (c) |
| iv | The line segment joining the midpoint of a side to opposite vertex is called ___ | median (a) |
| v | The angle bisectors of a triangle intersect at ___ | one point (a) |
| vi | Locus of points equidistant from a fixed point is ___ | circle (a) |
| vii | Locus of points equidistant from two fixed points is ___ | perpendicular bisector (b) |
| viii | Locus of points equidistant from a fixed line is / are ___ | parallel lines (d) |
| ix | Locus of points equidistant from two intersecting lines is ___ | angle bisector (c) |
| x | Farther than 2 km from a fixed point B is region outside circle of radius ___ | 2 km (c) |
Questions 2 - 4
Geometry Constructions
Q.2 Construct a right angled triangle with measures of sides 6cm, 8cm and 10cm.
Steps of Construction
- Draw line segment AB of length 6cm.
- At vertex B, construct an angle of 90°.
- With centre B and radius 8cm, draw an arc cutting the perpendicular ray at point C.
- Join C to A. Segment AC will measure 10cm by Pythagoras' theorem.
Q.3 Construct a triangle ABC with mAB = 5.3 cm, m∠A = 30° and m∠B = 120°. Draw right bisector of AB.
Steps of Construction
- Draw line segment AB of length 5.3cm.
- Construct an angle of 30° at point A and draw a ray.
- Construct an angle of 120° at point B and draw a ray. These rays intersect at point C.
- Draw the perpendicular right bisector line of the base segment AB.
Q.4 Construct a triangle with mDE = 7.3cm, m∠D = 42° and mEF = 5.4cm.
This is an **ambiguous case (SSA)** because the side opposite the angle (EF = 5.4cm) is shorter than the adjacent side (DE = 7.3cm) but longer than the altitude from E (\(h = 7.3 \sin 42^\circ \approx 4.88\)cm). This yields two valid intersection points F and F'.
Steps of Construction
- Draw segment DE of length 7.3cm.
- At vertex D, draw an angle of 42°.
- With centre E and radius 5.4cm, draw an arc cutting the angle ray at points F and F'.
- Join E to F and E to F' to form the two valid triangles ΔDEF and ΔDEF'.
Questions 5 - 8
Triangles & Regions
Q.5 Construct a triangle XYZ with mYX = 8cm, mYZ = 7 cm and mXZ = 6.5 cm. Draw a locus of all points which are equidistant from XY and XZ.
Steps of Construction
- Construct ΔXYZ using three sides SSS configuration.
- The locus of points equidistant from lines XY and XZ is the **angle bisector of vertex X**.
- Draw this bisector using compass arcs centered at vertex X.
Q.6 Construct triangle FGH with sides 6.4cm, angle 122°. Draw bisector loci.
Steps of Construction
- Draw base segment FG = 6.4cm. Construct angle 122° at G, cut at GH = 6.4cm to form isosceles triangle ΔFGH.
- Draw right bisector of FG (points equidistant from F and G).
- Draw angle bisector of ∠G (points equidistant from arms FG and GH).
- Mark their intersection as point O.
Q.7 Two houses Q and R are 73 metres apart. Locus 32m from Q and 48m from the line QR.
Geometric Analysis:
The locus 32m from Q is a circle of radius 3.2cm. The locus 48m from line QR consists of parallel lines at a distance of 4.8cm from QR. Since the circle has a maximum reach of 3.2cm from QR, it lies completely within the band between the two parallel lines. Thus, the loci do not intersect, and there are **no points** that satisfy both conditions simultaneously.
The locus 32m from Q is a circle of radius 3.2cm. The locus 48m from line QR consists of parallel lines at a distance of 4.8cm from QR. Since the circle has a maximum reach of 3.2cm from QR, it lies completely within the band between the two parallel lines. Thus, the loci do not intersect, and there are **no points** that satisfy both conditions simultaneously.
Q.8 Rectangle field ABCD (\(70\text{m} \times 60\text{m}\)). Show the region inside the field which is less than 30m from C and farther than 25m from AB.
Steps of Construction
- Using scale 1cm = 10m, draw rectangle ABCD of dimensions 7cm × 6cm.
- With centre C, draw a quarter circle of radius 3cm. The interior of this arc is the region less than 30m from C.
- Draw line segment PQ parallel to AB at a distance of 2.5cm. The area above this line is farther than 25m from AB.
- The intersection of these two regions (the shaded quarter-circle sector lying above the line PQ) is the required region.
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